Paragraph 1: Static electricity.
Exactly how and where would a static charge be deposited using PVC or rubber insulation and not using PTFE?
If you Google it, you’ll find there’s reasons for everything. It’s definitely because of the insulation and rated properties of the plastic
You’ll definitely have a solid reference for that then. Maybe a commercial application note describing failure modes caused by the use of something other than PTFE to insulate your leads and terminals
Electrical tape is 600V per wrap, by the way. Teflon tape is about 1kV per wrap. Neither are sufficient for insulating CO2 laser terminals, but because Teflon tape is so malleable you can easily use multiple wraps. Again, try doing that with any other insulating tape without damaging the terminal
But it has to reliably charge and discharge the high voltage in order to maintain timing with the head motion so it can project a cohesive image.
Sure. At what frequency? If we assumed the lead had a resistance of 1 ohm and the inter-lead capacitance is 500pF (which are ridiculously generous - actual values will be substantially lower) then the power supply can make use of frequency components up to 320MHz before you’ll see any distortion.
According to http://www.repairfaq.org/sam/laserco2.htm under “Electrical Modulation of a CO2 Laser” the laser itself will filter out any pulsing above a few kHz. I.e. above a few kHz, you will get a CW output regardless of the input.
Even if “capacitance” was a problem, what part of it will be effected by the terminal insulation?
- Capacitance between the two leads, which is substantial but entirely unaffected by the insulation on the terminals
- Capacitance between the two terminals which is entirely unsubstantial (very close to 0pF)
- Capacitance between the HV terminal and ground which is entirely unsubstantial (very close to 0pF)
Wrapping the terminal with PTFE rather than PVC will have no substantial effect on a capacitance that was not substantial to begin with